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[游戏] 21

此程序为21点扑克牌游戏,玩家一共可以要五张牌,但如果牌的点数超过21,则自动出局;在不超过21点的情况下,玩家与庄家比牌的点数大小,大者为赢,相同则为平局。 程序说明: 1) 将所有的函数与相应的数据封装到类中,并改写主程序。使程序简化。 2) 程序中一共有13张扑克牌可以随时抽取,大于10的点数为0.5。 3) 超级玩家永远不会输掉,即超级玩家可以查看下一张牌,若大于21点,则可以拒绝,当然游戏规则上不能泄露这点秘密。 4) 超级玩家可以查看下一张牌,即输入指定的字符串或字符,然后按要求输入正确密码后才能看自己的和计算机的牌,并指定下一级牌的点数。 5) 每次要牌后可以设定赔率,即如果开始下的是10元钱的注,如果牌好,你可以要求继续下注,当然不能超过你所有的总钱数。 6) 将界面的提示说明改成中文界面,界面的解释详细友好,可以吸引更多的玩家。
This procedure for the 21 points of the game, the player can be a total of five cards, but if the number of points more than 21, then automatically out in no more than 21 points, the players and the dealer than the number of points, the big winner, the same as a draw. Program description: 1) all the functions and the corresponding data are encapsulated in the class, and the main program is rewritten. Simplify procedures. 2) a total of 13 cards can be drawn at any time, more than 10 points to 0.5. 3) the super players will never lose, that is, the super players can look at the next card, if more than 21 points, you can refuse, of course, the game can not reveal this secret. 4) a super player can look at the next card, that is, enter the specified string or character, and then press the request to enter the correct password to see their own and the computer s card, and specify the next level. 5) every time you have to sign the odds, that if you start with a 10 yuan not (2015-09-02, Dev C++, 2KB, 下载5次)

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