开千年服务器就这样简单：
准备：
1、如想对外开放必须有公网IP（如果是网吧开放就需要在路由上做几个端口映射就可以了，一般是是80、3053、3054端口映射到你内部的IP。）
2、装有windows2000/2003系统、内存至少1G的电脑一台
3、得到千年服务器端一套
4、合理的调整方法
在压缩包内包含全部服务端全部文件：
1、人物部分属性查看器。
2、DB编辑器。
3、DB再线修改器。
This is how simple it is to open a millennium server:
get ready:
1. If you want to open to the outside world, you must have a public IP address (if you want to open an Internet bar, you need to map several ports on the route, generally 80, 3053, 3054 ports to your internal IP address.)
2. A computer with Windows 2000 / 2003 system and at least 1G memory
3. Get a set of Millennium server
4. Reasonable adjustment method
Include all server files in the compressed package:
1. Character part property viewer.
2. DB editor.
3. DB rewire modifier.
4. Emergency rate modification procedure: y1000sz.
5. Background logger: record 2000.
6. Modify the experience tool.
7. Millennium security strategy.
8. Millennium lander.
8. Millennium service controller.
9. Millennium equipment production tools.
10. Character changer.
11. Yaotian entertainment 1000y control tool v1.2.
12. The Chinese version of the Millennium server modification program.
13. Erection course (2020-06-13, C/C++, 566KB, 下载8次)
某幼儿园按如下方法依次给A，B，C，D，E五个小孩发糖果。将全部糖果的一半再加二分之一块糖果发给第一个小孩；将剩下糖果的三分之一再加三分之一块糖果发给第二个小孩；将剩下糖果的四分之一再加四分之一块糖果发给第三个小孩；将剩下糖果的五分之一再加五分之一块糖果发给第四个小孩；将最后剩下的11块糖果发给第五个小孩。每个小孩得到的糖果数均为整数。试确定原来共有多少块糖果？每个小孩各得到多少块糖果？
要求结果的输出格式为
sum＝糖果总数
xa＝A得到的糖果数
xb＝B得到的糖果数
xc＝C得到的糖果数
xd＝D得到的糖果数
xe＝E得到的糖果数
a kindergarten followed by the following method to the A, B, C, D, E five children made candy. Candy will be half plus half of the candy to the first block of a child; of the remaining one-third of the candy with candy third block to the second child; candy will be left with the fourth quarter to the third block candy child; candy will be left with the fifth block fifth candy to the fourth child; the last remaining 11 candy to the fifth child. Each child received a candy few are integral. The original trial to determine the total number of pieces of candy? Each of the children received how many pieces of candy? The results of the request output format for the total sum = candy xa = A number of the candy xb = B the candy few xc C = the number of candy xd = D The candy few xe E = the number (2006-05-04, C/C++, 1KB, 下载70次)