该Python代码模拟咖啡机，允许用户虚拟购买浓缩咖啡、拿铁或卡布奇诺。它跟踪配料（水、牛奶、咖啡），处理硬币付款，并提供报告。专为咖啡爱好者、程序员和企业主设计，探索咖啡选择、实践Python概念。
This Python code simulates a coffee machine, allowing users to virtually purchase espresso, latte, or cappuccino. It tracks ingredients (water, milk, coffee), processes coin payments, and provides reports. Designed for coffee enthusiasts, programmers, and business owners to explore coffee selection, practice Python concepts. (2024-03-10, Python, 0KB, 下载0次)
开发一个简化的工具，使用CSV文件中列出的企业识别号（CIN）从Finanvo轻松下载Bulk MCA V3文档。该项目旨在简化和加速检索过程，提高管理和访问关键财务文件的效率。
Developing a streamlined tool to effortlessly download Bulk MCA V3 documents from Finanvo using Corporate Identification Numbers (CIN) listed in a CSV file. This project aims to simplify and expedite the retrieval process, enhancing efficiency in managing and accessing crucial financial documents. (2024-01-30, Others, 0KB, 下载0次)
*注意-必须安装pygame才能运行此项目*此项目是一种尝试数据结构和解释器的方法，以获得一种高效和可读的方式，在类似rpg Rouge的概念中生成地下城。
*Note - You must have pygame installed to run this project* This project was a way to experiment with data structures and interpreters in order to get an efficient and readable way of producing dungeons in rpg roguelike concepts. (2023-07-31, Python, 0KB, 下载0次)
这是CS50x，哈佛大学为主修和非主修的计算机科学和编程艺术的智力企业做的介绍，有或没有编程经验。CS50x是David J.Malan教授的入门级课程，教学生如何进行算法思考并有效地解决问题。
This is CS50x , Harvard University s introduction to the intellectual enterprises of computer science and the art of programming for majors and non- majors alike, with or without prior programming experience. An entry-level course taught by David J. Malan, CS50x teaches students how to think algorithmically and solve problems efficiently. (2023-07-31, C, 0KB, 下载0次)
用图的机构表示实际的城际交通网络。
找到图中从某个源点到其余各顶点的最短路径。找到图中每一对顶点间的最短路径。
找到图中任意一对顶点间中转次数最少的路径。
Represents the actual use of intercity transportation network diagram institution.
Find the figure a source point to the rest of the shortest path to each vertex. Find the shortest path graph vertices of each pair.
Found between any pair of vertices of the smallest number of transit path diagram (2014-12-23, Visual C++, 1KB, 下载5次)
用哈夫曼编码原理，进行二元编码的过程。缩减信源符号数量。以达到数据压缩之效果
Huffman coding theory, carry out the process of binary encoding. Reduce the number of source symbols. In order to achieve the effect of data compression (2014-11-30, C#, 83KB, 下载4次)
二叉树的基本操作：建立、销毁、先序排序、中序排序、后序排序、广义表输出
The basic operation of a binary tree: create, destroy, first order sort, the sort order, the sort order, generalized table output
Google 翻译（企业版）：译者工具包网站翻译器全球商机洞察
关闭即时翻译关于 Google 翻译移动隐私权政策帮助发送反馈
(2014-06-06, Visual C++, 351KB, 下载3次)
企业已拥有定量资金，准备投资，有多个可供投资的项目，并可预知可供投资的项目的资金需求和投资回报率，求回报率最大化的投资组合。运用队列实现。
The companies already have quantitative funds are prepared to invest more available for investment in the project, can predict the demand for funds available for investment projects and ROI unrequited maximize portfolio. Use of queues realize. (2012-12-05, Visual C++, 332KB, 下载8次)
里面包含了各大企业面试用到的数据结构和算法 100道题目 有解答 很适合想去大公司或者挑战自己能力的人
Which contains 100 questions of the interview data structures and algorithms used major companies have answered very suitable for people who want to go to big companies or challenge their skills (2012-11-21, Visual C++, 2027KB, 下载6次)
VC/C++源码,随书源码,C语言《数据结构》全书全部源代码，随书源码下载，部分源码说明： c1-1.h 采用动态分配的顺序存储结构，Triplet类型是ElemType类型的指针，存放ElemType类型的地址； bo2-7.c 多项式(存储结构由c2-6.h定义)的基本操作及算法2.22、2.2...
运行环境：Windows/Visual C/C++
The VC/C++ source, with the source book, C language data structure book is full source code download with the source book, part of the source code Description: c1-1.h dynamically allocated sequential storage structure Triplet type is ElemType pointer Type the address of the store ElemType bo2 7.c polynomial (the storage structure by c2-6.h defined) basic operations and algorithms 2.22,2.2 ... operating environment: Windows/Visual C/C++ (2012-10-02, Visual C++, 3247KB, 下载3次)
一个典型的企业进、销、存管理信息系统的软件开发过程。内容包括系统的需求分析、建模分析、文件结构分析、数据结构分析、项目创建与设置、基础信息模块的创建、进货模块的创建、库存模块的创建、销售模块的创建等，涉及Java语育、管理、会计方面的知识
A typical business, sales, inventory management information systems software development process. Including system requirements analysis, modeling and analysis, document structure analysis, data structure analysis, project creation and set up, basic information module creation, creation of purchase module, inventory module creation, sales module creation, involving Java language education , management, accounting knowledge
(2012-02-01, Java, 19811KB, 下载6次)
要求：假定民航机场共有n个航班，每个航班有一航班号，确定的航线(起始站、终点站)、确定的飞行时间(星期几)和一定的成员定额，设计一民航订票系统，使之能提供下列服务：
1：航班信息录入功能(航班信
Located in Daxing Economic Development Zone, Beijing, China, Beijing Yashilin Testing Equipment Co., Ltd. (hereinafter referred to as “Yashilin”)specializes in manufacturing environment and reliability testing equipment. Having rich experience in the ring test industry ... (2011-12-19, Visual C++, 220KB, 下载2次)
题目：企业发放的奖金根据利润提成。利润(I)低于或等于10万元时，奖金可提10 ；利润高
于10万元，低于20万元时，低于10万元的部分按10 提成，高于10万元的部分，可可提
成7.5 ；20万到40万之间时，高于20万元的部分，可提成5 ；40万到60万之间时高于
40万元的部分，可提成3 ；60万到100万之间时，高于60万元的部分，可提成1.5 ，高于
100万元时，超过100万元的部分按1 提成，从键盘输入当月利润I，求应发放奖金总数？
is my life (2011-11-19, C/C++, 1KB, 下载2次)
有个国有中型企业，接到一批需要加工零件的订单，员工们非常高兴，可是高兴之后却发现问题了，原来这家企业能够加工这批零件的机床有限，如果仅仅为了这批加工任务而新添机床的话，那么既不合算也不必要，因为加工完这批零件后很可能这些机床又要闲置起来，所以大批量购买肯定不行，但这批订单又必须要完成，那么这么办呢？很想请你帮忙设计一个加工任务的顺序，使得完成这批订单所需要使用的机床数量最少。
There is a state-owned medium-sized enterprises, received a batch of orders for parts to be machined, the staff are very happy, but happy to have found the problem after the original processing of this enterprise to a limited group of machine parts, if only for these processing tasks added a new machine, then both uneconomical and unnecessary, because the processing after completion of these parts may have to idle up these machines, so the bulk purchase will not do, but these orders must also be completed, then so should we do? Would like to ask you to help design a sequence of processing tasks, making the completion of these orders need to use the least number of machines. (2011-10-26, Visual C++, 1KB, 下载3次)
控制台程序，用于拷贝一个二进制文件，并从别外一个Ｃ文件中读取某一字符串作为拷贝文件的名称。
copy a binary file and rename it that the name read from the other c file.
you can use the console execute it .
EG.changename cn (2011-04-02, Visual C++, 4142KB, 下载2次)
贪婪算法的具体例子
有个国有中型企业，接到一批需要加工零件的订单，员工们非常高兴，可是高兴之后却发现问题了，原来这家企业能够加工这批零件的机床有限，如果仅仅为了这批加工任务而新添机床的话，那么既不合算也不必要，因为加工完这批零件后很可能这些机床又要闲置起来，所以大批量购买肯定不行，但这批订单又必须要完成，那么这么办呢？很想请你帮忙设计一个安排加工任务，使得完成这批订单所需要使用的机器数量最少
An example of greedy method (2010-09-01, Visual C++, 190KB, 下载4次)
包括huffman编码的源代码
输入为信源符号个数信源的概率分布
输出为每个符号对应的huffman编码的码字
Including the source code for huffman encoding source input for the number of source symbols of the probability distribution of output for each symbol corresponding to the codeword huffman coding (2009-06-02, Visual C++, 1KB, 下载4次)
一元稀疏多项式计算器的基本功能是：
(1)输入并建立多项式；
(2)输出多项式，输出形式为整数序列：n,c1,e1,c2,e2,….,cn,en, 其中n是多项式的项数，ci和ei分别是第I项的系数和指数，序列按照指数降序排列；
（3）多项式a和b相加，建立多项式a+b
（4）多项式a和b相减，建立多项式a-b.
Sparse Polynomial calculator a dollar a basic function is to: (1) input and the establishment of polynomials (2) the output polynomial, the output sequence of the form of an integer: n, c1, e1, c2, e2, ...., Cn , en, in which n is the number of polynomial, ci and ei, respectively, is the first I of the coefficient and index, sequence in accordance with the index in descending order (3) polynomials a and b are added together to establish polynomial A2B ! b (4) polynomials a and b-phase reduction, the establishment of polynomial ab. (2008-09-19, C/C++, 11KB, 下载14次)
判定一个码是否为唯一可译码
1. 已知：信源符号个数为q，码符号集为C
2. 输入：任意一个码。码字个数和每个具体的码字在运行时从键盘输入。
3. 输出：判断（是否唯一可译码）
1 yards to determine whether only one decoder. Known: the number of source symbols for q, code symbol set for C2. Input: arbitrary one yards. Code word and every specific number of characters in the run-time code from the keyboard input. 3. Output: to determine (whether or not the only decoding) (2008-06-04, C/C++, 1KB, 下载16次)
信息论与编码报告。内源程序为： 对给定信源符号进行哈夫曼编码，然后输出码字，平均码长，信息传输率。
Report of information theory and coding. Within the source as follows: for a given source symbols Huffman encoding, and then the output codeword, the average code length, information transfer rate. (2007-10-16, WORD, 26KB, 下载48次)