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[其他] 缠论中枢(指标 主图 通达信 贴图)无加密

论中枢(指标 主图 通达信 贴图)无加密 缠师说,有多少不同构的自同构结构,就有多少种分析股市的正确道路。若按缠师的顶底分型有新笔、旧笔之争,本人按均线,同样可以找到一种自同构性,而且简单,当然均线可以改成很多其它的指标,同样可以完整展示整个中枢形成的过程,股票的前世今生完全体现
DLL:=TDXDLL1(1,H,L,5); HIB:=TDXDLL1(2,DLL,H,L); LOB:=TDXDLL1(3,DLL,H,L); SIG:=TDXDLL1(4,DLL,H,L); BSP:=TDXDLL1(5,DLL,H,L); SLP:=TDXDLL1(8,DLL,H,L); IF(HIB,HIB,DRAWNULL), COLORYELLOW; IF(LOB,LOB,DRAWNULL), COLORYELLOW; STICKLINE(SIG,LOB,HIB,0,0), COLORYELLOW; DRAWLINE(DLL=-1,L,DLL=+1,H,0), COLORYELLOW; DRAWLINE(DLL=+1,H,DLL=-1,L,0), COLORYELLOW; DRAWNUMBER(DLL=+1,H,SLP), COLORYELLOW, DRAWABOVE; DRAWNUMBER(DLL=-1,L,SLP), COLORYELLOW; BUY(BSP=3,LOW); SELL(BSP=12,HIGH); BUYSHORT(BSP=2,LOW); SELLSHORT(BSP=13,HIGH); (2020-03-30, Visual C++, 4KB, 下载5次)

http://www.pudn.com/Download/item/id/1585554161305231.html

[其他] 火车头软件V7.6企业版_破解

CorelDRAW Graphics Suite是加拿大Corel公司的平面设计软件;该软件是Corel公司出品的矢量图形制作工具软件,这个图形工具给设计师提供了矢量动画、页面设计、网站制作、位图编辑和网页动画等多种功能。
CorelDRAW Graphics Suite is a graphic design software Corel company of Canada; the vector graphics software is produced by Corel company production tools, this tool provides a graphical function of vector animation, page design, website production, web animation and bitmap editing to the designer. (2018-03-18, Visual C++, 42970KB, 下载5次)

http://www.pudn.com/Download/item/id/1521303165304742.html

[其他] 新建文件夹

企业发放的奖金根据利润提成。利润(i)低于或等于10万元时,奖金可提10%;利润高? ???于10万元,低于20万元时,低于10万元的部分按10%提成,高于10万元的部分,可可提? ???成7.5%;20万到40万之间时,高于20万元的部分,可提成5%;40万到60万之间时高于? ???40万元的部分,可提成3%;60万到100万之间时,高于60万元的部分,可提成1.5%,高于? ???100万元时,超过100万元的部分按1%提成,从键盘输入当月利润i,求应发放奖金总数?? 1.程序分析:请利用数轴来分界,定位。注意定义时需把奖金定义成长整型。???????2.程序源代码:
The bonus paid by the enterprise is made according to the profit. Profit (I) less than or equal to 100 thousand yuan, money can be raised 10%; high profit To 100 thousand yuan, less than 200 thousand yuan, 100 thousand yuan less than the part of the 10% Commission, more than 100 thousand yuan, cocoa 7.5%; 200 thousand to 400 thousand, more than 200 thousand yuan, the Commission 5%; 400 thousand to 600 thousand higher than 400 thousand yuan, the Commission 3%; 600 thousand to 1 million, more than 600 thousand yuan, to the Commission of 1.5%, higher than 1 million yuan, 1 million yuan more than part of the 1% Commission, from the keyboard input I month profit, seek the total number of bonuses? 1. program analysis: please use a few axes to boundaries, positioning. When you pay attention to definition, you need to define the bonus as an integer. 2. source code: (2018-01-02, Visual C++, 1KB, 下载1次)

http://www.pudn.com/Download/item/id/1514908139274791.html

[其他] 50个C、C++面试题

c/c++面试,各大企业招聘人才,笔试、面试题
using for c/c++ written examination and interview (2017-09-03, Visual C++, 498KB, 下载12次)

http://www.pudn.com/Download/item/id/1504448107444485.html

[其他] 龙与地下城角色生成

游戏角色应有以下属性:名字、性别、种族、职业、力量、敏捷、体力、智力、智慧、生命值和魔法值。 名字:不超过50个字符。 性别:可以选择男性和女性。 种族:一共可选五个种族,人类、精灵、兽人、矮人和元素。 职业:可选六种职业,狂战士、圣骑士、刺客、猎手、祭司和巫师。 其余属性均为整数。 本题目要求首先用户输入角色姓名,然后由用户选择角色性别,然后由用户选择种族,然后选择职业,然后自动分配力量、敏捷、体力、智力和智慧属性,并计算生命值和魔法值。 生命值=体力*20。 魔法值=(智力+智慧)*10。
Game characters should have the following attributes: name, gender, race, occupation, strength, agility, stamina, intelligence, intelligence, life values, and magic values. Name: no more than 50 characters. Sex: men and women are available. Ethnicity: a total of five races, humans, elves, orcs, dwarves, and elements. Occupation: there are six occupations available: Berserker, Paladin, assassin, hunter, priest and sorcerer. The remaining attributes are integers. This topic request user input character name first, and then selected by the user and by the user to select the role of gender, race, and then choose the occupation, and automatic distribution of strength and agility, strength, intelligence and wisdom of the property, and calculate the value of life and mana. Life = physical strength *20. Mana = (intelligence + wisdom) *10. (2017-06-28, Visual C++, 5409KB, 下载1次)

http://www.pudn.com/Download/item/id/1498656992387796.html

[其他] mpias

ML法能够很好的估计信号的信噪比,虚拟力的无线传感网络覆盖,电力系统暂态稳定程序,可以进行暂态稳定计算。
ML estimation method can be a good signal to noise ratio, Virtual power wireless sensor network coverage, Power System Transient Stability Program, can be transient stability. (2017-05-02, Visual C++, 6KB, 下载1次)

http://www.pudn.com/Download/item/id/1493696083556222.html

[其他] Interview

此文档是百度面试题目的相关文档,有助于百度面试,使你迅速进入大企业...
This document is Baidu interview questions related documentation and help Baidu interview, so that you quick access to large enterprises ... (2013-10-10, Visual C++, 757KB, 下载3次)

http://www.pudn.com/Download/item/id/2371051.html

[其他] bianchentimu

各种小的编程题目,适合于大学毕业生,研究生毕业准备招聘公司的考试,大部分来自企业的往年考题,希望对你有帮助
All sorts of small programming topic, suitable for college graduates, graduate recruitment company to test, mostly from enterprise s usual questions, the hope is helpful to you (2012-12-18, Visual C++, 36KB, 下载3次)

http://www.pudn.com/Download/item/id/2087484.html

[其他] S7rrart

本课题所研究的可存储虚拟示波器定位为低档型,即在性能上只需满足大多场合的基本应用,努力实现小型化,价格尽可能低廉,这样在财财力有限的小用户(电子爱好者、小型企业)中能够普及,在大用户的使用中发挥便携性强强的优势,与高档示波器配合使用,互相取长补短。
Research in this subject can be stored in virtual oscilloscope positioned as a low-grade type, that is just in the performance to meet most of the basic application of the occasion, and strive to achieve the miniaturization, low price as much as possible, so that the fiscal and financial resources limited user (electronic enthusiasts. small business) popularized the use of large users to play the advantages of portability powerful and high-end oscilloscope used in conjunction with and complement each other. (2012-08-03, Visual C++, 633KB, 下载4次)

http://www.pudn.com/Download/item/id/1956154.html

[其他] WhMgr

利用vc++6.0实现企业应用中 涉及到物资管理系统,使用本系统可以完成物资的入库,出库,借用和归还等操作
Using vc++6.0 involved in enterprise application materials management system, the system can be completed using materials storage, a library, borrow and return of such operations (2011-05-26, Visual C++, 124KB, 下载2次)

http://www.pudn.com/Download/item/id/1548110.html

[其他] jiandanlianbiaoguanliyuangong

从键盘输入4位员工的信息到动态创建的线性单向链表中;然后通过访问该链表,将其中的所有节点中的员工信息存放到文件myfile.dat中。每位员工的信息如下: 杜永宁 软件部 5760 王传华 销售部 3920 殷 泳 培训部 2940 杨柳青 软件部 5440。
From the keyboard input four employees to create dynamic information of linear one-way list, Then through the list, will visit them all the staff information storage nodes in myfile to file landuse-dat j. Each employee information below: DuYongNing software WangChuanHua sales 3920 5760 department Yin swimming training new software 5440 department 29.4. (2010-09-08, Visual C++, 1KB, 下载2次)

http://www.pudn.com/Download/item/id/1292102.html

[其他] jiamijiemi

这只是一个“简明教程”了。还是那句话——“本文仅供朋友们“消遣作乐”,。如果你觉得没什么意思的话,一笑了之。仅供娱乐而已,不必太过认真。”
This is just a " simple tutorial" the. Then again- " This only friends" recreational merry " . If you think there is any meaning, then laugh. Only for entertainment only, do not be too serious." (2010-03-22, Visual C++, 2KB, 下载2次)

http://www.pudn.com/Download/item/id/1095788.html

[其他] uniquely_decodable_code

信息论课程设计: (1)已知:信源符号个数 、码字集合 ; (2)输入:任意的一个码字集合 。码字个数和每一个具体的码字在运行时从键盘输入; (3)输出:判决(是惟一可译码/不是惟一可译码)。
Information theory, curriculum design: (1) is known: the number of source symbols, code word set (2) Input: an arbitrary set of a code word. Code word a specific number and each code word in the run-time input from the keyboard (3) Output: decision (which is the only available coding/decoding is not the only available). (2010-02-18, Visual C++, 1KB, 下载5次)

http://www.pudn.com/Download/item/id/1065427.html

[其他] ATmega88_cn

ATmega48/88/168产品特性 • 高性能、低功耗的8 位AVR® 微处理器 – 256/512/512 字节的EEPROM (ATmega48/88/168) 擦写寿命: 100,000 次 – 512/1K/1K 字节的片内SRAM (ATmega48/88/168) – 具有独立振荡器的实时计数器RTC – 六通道PWM – 8路10 位ADC(TQFP 与MLF 封装) – 6路10 位ADC( PDIP 封装) – 可编程的串行USART 接口 – 可工作于主机/ 从机模式的SPI 串行接口
ATmega48/88/168 Product Features • High-performance, low power 8-bit AVR ® microcontroller- 256/512/512 bytes EEPROM (ATmega48/88/168) rewritable Life: 100,000- 512/1K/1K bytes of on-chip SRAM (ATmega48/88/168)- real-time counter with separate oscillator RTC- 6-channel PWM- 8 channel 10-bit ADC (TQFP and MLF packages)- 6-channel 10-bit ADC (PDIP Package )- Programmable Serial USART interfaces- can operate in master/slave mode SPI serial interface (2009-10-16, Visual C++, 2491KB, 下载52次)

http://www.pudn.com/Download/item/id/939604.html

[其他] ATmega64_cn

AVR single-chip developed by a very low threshold, as long as the computer will be able to study the development of AVR microcontroller. Only a single-chip ISP download beginners line, the editing, debugging of software programs through a direct line into the AVR microcontroller, which can develop AVR Series Single-chip package of a variety of devices. AVR single-chip microcomputer in the industry known as "front-line struggle to seize state power."
AVR single-chip developed by a very low threshold, as long as the computer will be able to study the development of AVR microcontroller. Only a single-chip ISP download beginners line, the editing, debugging of software programs through a direct line into the AVR microcontroller, which can develop AVR Series Single-chip package of a variety of devices. AVR single-chip microcomputer in the industry known as "front-line struggle to seize state power." (2009-05-22, Visual C++, 2301KB, 下载36次)

http://www.pudn.com/Download/item/id/772662.html

[其他] DUMPROM

DumpROM工具,可以更改WM的软件。
DumpROM tool, you can change the WM software. (2008-11-20, Visual C++, 1419KB, 下载632次)

http://www.pudn.com/Download/item/id/584536.html

[其他] xinxilunyubianma

信息论与编?氲牟街? (1). 把信源符号按概率大小顺序排列, 并设法按逆次序分配码字的长度。 (2). 在分配码字长度时,首先将出现概率 最小的两个符号的概率相加合成一个概率 (3). 把这个合成概率看成是一个新组合符号地概率,重复上述做法直到最后只剩下两个符号概率为止。 (4). 完成以上概率顺序排列后,再反过来逐步向前进行编码,每一次有二个分支各赋予一个二进制码,可以对概率大的赋为零,概率小的赋为1。 (2008-05-15, Visual C++, 2KB, 下载2次)

http://www.pudn.com/Download/item/id/463649.html

[其他] hefu

哈夫曼编码的步骤: (1). 把信源符号按概率大小顺序排列, 并设法按逆次序分配码字的长度。 (2). 在分配码字长度时,首先将出现概率 最小的两个符号的概率相加合成一个概率 (3). 把这个合成概率看成是一个新组合符号地概率,重复上述做法直到最后只剩下两个符号概率为止。 (4). 完成以上概率顺序排列后,再反过来逐步向前进行编码,每一次有二个分支各赋予一个二进制码,可以对概率大的赋为零,概率小的赋为1。 (2008-05-15, Visual C++, 1KB, 下载5次)

http://www.pudn.com/Download/item/id/463647.html

[其他] StateUBookstore1

这是根据清华大学出版社《全面掌握vb6.0企业应用程序开发》修改而成,集中这六七年自学的心血,希望大家提出批评和指正
This is based on the Tsinghua University Publishing House, "a comprehensive master vb6.0 Enterprise Application Development" and revisions. 67 focus on this self-made on the hope that we criticize and correct (2007-05-17, Visual C++, 1KB, 下载1次)

http://www.pudn.com/Download/item/id/283361.html

[其他] gpsdata

这是一个将数据转化为车辆监控系统的gps数据包的源代码,重载了两个函数。分别对应不同的结构定义
This is a data conversion system for the vehicle of a GPS monitoring data packet's source code, the two heavy-duty function. Dealing with different definition of the structure (2005-08-10, Visual C++, 29KB, 下载34次)

http://www.pudn.com/Download/item/id/106898.html
总计:106