1. 约瑟夫（Joseph）问题的一种描述是：编号为1,2，…，n的n个人按顺时针方向围坐一圈，每人持有一个密码（正整数）。一开始任选一个正整数作为报数上限值m，从第一个人开始按顺时针方向自1开始顺序报数，报到m时停止报数。报m的人出列，将他的密码作为新的m值，从他在顺时针方向上的下一个人开始重新从1报数，如此下去，直至所有人全部出列为止。试设计一个程序求出出列顺序。
2. 演示程序以用户和计算机的对话方式进行，即在计算机终端上显示“提示信息”之后，由用户在键盘上输入演示程序中规定的运算命令；相应的输入数据（滤去输入中的非法值）和运算结果显示在其后。
3. 程序不得采用公式计算等其他数学方式求解。
4. 测试数据：
1. A description of Joseph (Joseph) the problem is: numbered 1,2, ..., n by n individuals sitting clockwise circle, each holding a password (positive integer). Optionally start a positive integer as the number of reported upper limit of m, the first person to embark on the clockwise direction a starting sequence number off, stop newspaper report the number of hours m. Reported m people out of the column, his password as a new m value, starting his next person in a clockwise direction one number off again, and so on, until everyone up all the columns. Try to design a program to determine the order of the columns.
2. demonstration program in dialogues users and computers, namely after displaying message , input by the user demo predetermined arithmetic commands at the keyboard on the computer terminal illicit corresponding input data (filtered inputs value) and the results are shown in the subsequent operation.
3. The program shall not be used other mathematically calculated and (2015-07-13, C++, 1KB, 下载6次)
奇迹(MU)通用登陆器 适用于私服站长配置后给玩家下载使用. 其中在设置中ip加了密,端口文件放在WEB服务器器上,只需设置 web文件地址即可(地址也加了密)例如:端口文件是 http://www.1234.com/dk/123.txt (当然也可以是*.ini或*.dat或*.*) (那么你以后更改端口只需更改123.txt里面 1.你编译的主程序文件 (名字由你随便改) 2.ckh.exe (窗口化工具,我们要调用的)提示:窗口化工具不用理它,都可以在登陆器设置,但不用关闭它.... 3.hook.dll (有它 窗口化工具 才能正常运行) 4.Option.ini (记录你配置的ip和端口文件地址以及其它的一些西西) 5.readme.htm (内容随你改!) 6.logo.jpg (你家奇迹的logo,谁你改,你怎么配置怎么画都可以-_-!)
Miracle (MU) General landers Sifu configured for owners to download the player. Ip in the settings of which added a secret, port file on the WEB server, device, simply set th web document address below (address also included a secret) For example: port file is http://www.1234.com/dk/123.txt (of course, can also be a*. ini or*. dat or*.*) (Then you only need to change the future to change the port inside 123.txt 1. Do you compile the main program file (you just change the name from) 2.ckh.exe (window-based tools, we have to call) Tip: Windows-based tool that is not of it, can be set up in the landers, but do not close it .... 3.hook.dll (has its own window tools to work properly) 4.Option.ini (record your ip and port configuration file address, as well as some other cc) 5.readme.htm (content as you change!) 6.logo.jpg (a miracle in your house logo, change who you are, how do you configure how art can be-_-!) 7.MSINET.OCX (vb of a control, the remote server por (2014-12-16, Visual C++, 1KB, 下载3次)
用C山寨的NTLEA, 基本原理就是 hook 各种 ansi API, 用指定 codepage 转成 unicode 后, 直接调用 unicode API
比较复杂的是各种带字符串的窗口消息, 因为这部分的转换是在内核进行的, 所以要hook的函数比较多, 而且各种ansi to unicode, unicode to ansi得自己调用
以下是NTLEA的介绍:
NTLEA （NT Locale Emulator Advance），是一个区域及内码转换软件。专门用来解决游戏或软件乱码。尤其是喜欢玩日语游戏的小众读者一定要好好关注此文。
NTLEA 也可以拿来处理乱码的 txt，不过它并不是什么乱码都能处理。假如你收到乱码的邮件想用它来处理的话，有点大材小用了。把你的乱码邮件转发到 Gmail，一般就可以解决。
With C cottage NTLEA, helps understanding between ANSI and UNICODE window conversion call NTLEA (NT Locale Emulator Advance), is a regional and internal code conversion software. Designed to solve the game or software garbled. Especially like to play Japanese games niche readers must be properly concerned about this article. NTLEA can also be used to deal with garbled txt, but it can handle is not garbled. If you want to use it to process messages received garbled overkill. Your garbled e-mail forwarded to Gmail, generally can be resolved. (2012-09-08, Visual C++, 10KB, 下载16次)
魔兽游戏里踢人
我们HOOK Send函数。如果我们和某个玩家私聊，假设输入7720668，那么肯定可以在pBuffer中搜索到这个字符串，然后我们关闭相应的socket即可实现T人了。（这里也说明了:只有主机才可以T人。因为通过伪造TCP、SYN、ACK数据包来实现，几乎不可能）
World of Warcraft game kicking us HOOK Send function. If we whisper a player, assuming that the input 7,720,668, then certainly in the pBuffer search to this string, and then we close the socket to achieve the appropriate T people. (This also explains: T can only host one, because by forging TCP, SYN, ACK packet to achieve, almost impossible) (2011-07-05, Visual C++, 39KB, 下载23次)