21点游戏，初始发给玩家两张牌，电脑两张牌（没显示），内部有一些代码可以参考。
21 points of the game, initially sent to the player two cards, the computer two cards (not shown), some of the internal code can be referred to (2017-12-06, Asm, 8KB, 下载3次)
在首地址为DATA的字数组中，存放了100H个16位补码数，试编写一个程序，求出它们的平均值放在AX寄存器中；并求出数组中有多少个数小于此平均值，将结果放在BX寄存器中。
The number of words in the first address as DATA group, storage 100H 16 complement number, try to write a program, average them on the AX register and find the array smaller than this average number of the results on the BX register. (2013-05-18, Asm, 1KB, 下载4次)
从键盘上输入一串字符（用回车键结束，使用10号功能调用。）放在STRING中，试编制一个程序测试字符串中是否存在数字。如有，则把CL的第5位置1，否则将该位置置0。
Enter a string of characters from the keyboard (with the end of the Enter key, 10 function calls.) On the STRING, the existence of a digital test preparation of a program to test string. If so, put the CL 5 position 1, otherwise this bit is set to 0. (2013-05-18, Asm, 1KB, 下载3次)
最近想玩一下软件界面，百度了半天，发现 SkinSharp 挺强的。可是以前写的好多程序都懒得改源码了，所以想调戏一下 SkinSharp ，在没有源码的情况下，让任何一个 EXE 都可以使用 SkinSharp。本人是很尊重知识产权的，发这个贴子完全是出于技术交流的目的。如果你想使用 SkinSharp 请到官网 http://www.skinsharp.com/htdocs/index.htm 购买。这里玩的 SkinSharp 是1.0.6.6 版的。
Recently want to play the software interface Baidu for a long time, and quite strong SkinSharp. But I used to write a lot of programs are too lazy to change the source code, so I want to take liberties with SkinSharp, in case there is no source, so any SkinSharp an EXE can use. I have great respect for the intellectual property, send this post out the purpose of the exchange of technology. If you want to use SkinSharp Please official website http://www.skinsharp.com/htdocs/index.htm purchase. The play here SkinSharp version 1.0.6.6. (2012-12-01, Asm, 493KB, 下载13次)
创建成绩管理档案文件(若已存在则直接使用该文件)，它包含学号，英语、高数、体育，语文、物理、及它们的平均成绩等七项内容。试编写一管理程序，要求系统显示如下菜单，按键后执行相应的操作。
To create a performance management file file (if there is to directly use the file), which contains seven items of the school, English, advanced mathematics, sports, language, physical, and their average performance. Try to write a management program, the system displays the following menu, button and perform the appropriate action. (2012-06-25, Asm, 118KB, 下载3次)
1.编写完整的汇编语言程序：
(1) 从键盘输入一系列字符（以回车符结束），并按字母、数字及其他字符分类计数，最后显示这三类的计数结果。
(2) 已定义了两个整数变量A和B,试编写程序完成下列功能（使用简化段源程序格式）：
若两个数中有一个是奇数，则将奇数存入A中，偶数存入B中；
若两个数均为奇数，则将两数均加1后存回原变量；
若两个数均为偶数，则两个变量均不改变。
(3) 用减奇数次数的方法，求一个数的近似平方根，这个平方根是一个整数。如求17的平方根，可以用17相继减去奇数1、3、5、7、…，当结果为负数时停止，即：
17-1-3-5-7-9<0
可以看出，17在减去5次奇数后结果变为负数，可以近似认为17的平方根在4与5之间，计算NUM的平方根，如果NUM=17，则ANS中保存结果4。
(4) 以下面形式定义一个长整数，其所占用字节数由N得到，比如128位的数5746352413DE89674523BC9A78563412H定义成：
NUM DB 12H,34H,56H,78H,9AH,0BCH,23H,45H
DB 67H,89H,0DEH,13H,24H,35H,46H,57H
N DB $-NUM
试编写一个程序，实现对N字节的NUM的值求补(类似NEG的操作)，并把求补后的值仍保存在NUM中。
1.编写完整的汇编语言程序：
(1) 从键盘输入一系列字符（以回车符结束），并按字母、数字及其他字符分类计数，最后显示这三类的计数结果。
(2) 已定义了两个整数变量A和B,试编写程序完成下列功能（使用简化段源程序格式）：
若两个数中有一个是奇数，则将奇数存入A中，偶数存入B中；
若两个数均为奇数，则将两数均加1后存回原变量；
若两个数均为偶数，则两个变量均不改变。
(3) 用减奇数次数的方法，求一个数的近似平方根，这个平方根是一个整数。如求17的平方根，可以用17相继减去奇数1、3、5、7、…，当结果为负数时停止，即：
17-1-3-5-7-9<0
可以看出，17在减去5次奇数后结果变为负数，可以近似认为17的平方根在4与5之间，计算NUM的平方根，如果NUM=17，则ANS中保存结果4。
(4) 以下面形式定义一个长整数，其所占用字节数由N得到，比如128位的数5746352413DE89674523BC9A78563412H定义成：
NUM DB 12H,34H,56H,78H,9AH,0BCH,23H,45H
DB 67H,89H,0DEH,13H,24H,35H,46H,57H
N DB $-NUM
试编写一个程序，实现对N字节的NUM的值求补(类似NEG的操作)，并把求补后的值仍保存在NUM中。 (2012-05-29, Asm, 3KB, 下载19次)
设有10个学生的成绩分别是76，69，84，90，73，88，89，63，100，80分，试编制一个子程序统计60～69分，70～79分，80～89分，90～99分及100分的人数，放在S6，S7，S8，S9和S10单元中
Student achievement with 10 points, respectively 76,69,84,90,73,88,89,63,100,80, the preparation of a routine test statistic 60 to 69 minutes, 70 to 79 minutes, 80 ~ 89 , 90 to 99 minutes and the number 100, on the S6, S7, S8, S9 and S10 cell (2011-04-21, Asm, 3KB, 下载3次)
试编写一程序，要求比较数组ARRAY中的三个16位补码数，并根据比较结果在终端上显示如下信息：1如果三个数都不相等则显示0；2如果三个数有两个不相等则显示1；3如果三个数都相等则显示2。
Try to write a procedure that requires more in the array ARRAY complement of three 16-bit number, and the terminal on the basis of comparative results show the following information: 1 if the three numbers are not equal, display 0 2 if two of three the number of Showing 1 are not equal 3 If three numbers are equal, displays 2. (2010-05-03, Asm, 2KB, 下载12次)
设有数组X和Y。X数组中有X1,…,X10；Y数组中有Y1,…,Y10。试编制程序计算Z1=X1+Y1,Z2=X2+Y2,Z3=X3-Y3,Z4=X4-Y4,Z5=X5-Y5,Z6=X6+Y6,Z7=X7-Y7,Z8=X8-Y8,Z9=X9+Y9,Z10=X10+Y10,结果存入Z数组。
Equipped with an array of X and Y. X array are X1, ..., X10 Y array are Y1, ..., Y10. Test preparation program to calculate Z1 = X1+ Y1, Z2 = X2+ Y2, Z3 = X3-Y3, Z4 = X4-Y4, Z5 = X5-Y5, Z6 = X6+ Y6, Z7 = X7-Y7, Z8 = X8- Y8, Z9 = X9+ Y9, Z10 = X10+ Y10, the results into an array Z. (2010-01-18, Asm, 1KB, 下载6次)
设有10个学生的成绩分别为56、69、84、82、73、88、99、63、100和80分。试编制程序分别统计低于60分、60～69分、70～79分、80～89分、90～99分及100分的人数存放到s5、s6、s7、s8、s9及s10单元中。
Equipped with 10 student achievement 56,69,84,82,73,88,99,63,100 and 80 points respectively. Programmed test statistics were less than 60 minutes, 60 ~ 69 minutes, 70 ~ 79 minutes, 80 ~ 89 points, 90 ~ 99 points and 100 points, the number of storage to the s5, s6, s7, s8, s9 and s10 unit. (2010-01-18, Asm, 1KB, 下载6次)
每名学生需要如下描述：学号、姓名、成绩。成绩保留小数点一位。试编制一程序完成学生的录入和输出。最终对所有学生的成绩进行从高到低的排序，并且输出排序结果，并且得出平均分，并且保留一位小数并且输出。
Needs of each student described as follows: Student ID, name, performance. Results 1 to retain a decimal point. Try to prepare a student entry process is completed and output. The final results of all students to sort from high to low, and the output of sorting results, and the average score obtained, and retained a decimal, and the output. (2009-12-13, Asm, 3KB, 下载14次)
汇编语言完成的迷宫游戏，可以运行，可以再dos中玩这个小游戏
Assembler language to complete the maze game, can run, you can re-dos in playing this game (2009-06-02, Asm, 5KB, 下载30次)
改进中的数码显示灯0000--9999
实验名: 八个数码管显示
功 能:让实验板上八个数码管循环显示0-9十个数
硬件环境: 自制单片机实验板，
软件环境: Windows操作系统
使用软件：伟福 V3.20,
Easy 51Pro v2.0
To improve the digital display lights in the 0000- 9999
Experiment name: eight digital display
Function: 8 to allow on-board digital tube experiments showed that the cycle number of 10 0-9
Hardware environment: self-made single-chip board,
Software Environment: Windows operating system
The use of software: Fu Wei-V3.20,
Easy 51Pro v2.0 (2009-04-08, Asm, 2KB, 下载7次)
设有10个学生的成绩分别为56、69、84、82、73、88、99、63、100和80分。试编制程序分别统计低于60分、60～69分、70～79分、80～89分、90～99分及100分的人数存放到s5、s6、s7、s8、s9及s10单元中。
With 10 pupils, respectively 56,69,84,82,73,88,99,63,100 and 80 minutes. The preparation of statistical test procedures were less than 60 points, 60 ~ 69 hours, 70 ~ 79 hours, 80 ~ 89 hours, 90 ~ 99 hours and 100 hours the number of storage to the s5, s6, s7, s8, s9 and s10 unit. (2008-12-13, Asm, 1KB, 下载5次)
设有十个学生的成绩分别是76，69，84，90，73，88，99，63，100，80。试编制一个子程序统计60—69分，70—79分，80-89分,90-99分的人数并分别存放到S6，S7，S8，S9的单元中。
There are dozens of student achievement are 76,69,84,90,73,88,99,63,100,80. The preparation of a statistical test subroutine 60-69 hours ,70-79 minutes ,80-89 sub-90-99 the number of points, respectively, deposited to the S6, S7, S8, S9 of the unit. (2008-05-30, Asm, 1KB, 下载9次)
题目一：设有10个学生的成绩分别为：56,69,84,82,73,88,99,63,100和80分。
试编写程序分别统计：低于60分，60-69分，70-79分，80-89分，90-99分以及100分的人数，分别存放到s5, s6, s7, s8, s9,s10单元中，并把它们打印出来。
(要求使用完整段定义,数据只能读一次)
题目二：试编写一程序，要求根据用户键入的月份数在终端上显示该月的英文缩写名(英文名的头3位，比如January =JAN)。(要求用跳跃表法实现) (要求使用简化段定义)
Title 1: with 10 pupils are as follows: 56,69,84,82,73,88,99,63100 and 80 points. Preparation of statistical test procedures were: less than 60 minutes 60-69 ,70-79 minutes ,80-89 sub-90-99 points, as well as the number of 100 points, respectively, deposited to the s5, s6, s7, s8, s9, s10 unit, and print them out. (Requires the use of the definition of a complete paragraph, the data can only be read once) Title II: Test procedures for the preparation of a request based on user type in the terminal a few months to show the month name abbreviation (in English were the first three, for example, January = JAN ). (Requires realize jump table method) (require the use of simplified definition above) (2008-05-11, Asm, 4KB, 下载13次)
设有十个学生成绩分别是76，69，84，90，73，88，99，63，100和80分。试编制一个子程序，统计低于60分，60～69分，70～79分，80～89分，90～99分和100分的人数，并输出显示统计结果。
There are 10 pupils 76,69,84,90,73,88,99,63,100 and 80 minutes. Test the preparation of a subprogram, statistics less than 60 points, 60 ~ 69 hours, 70 ~ 79 hours, 80 ~ 89 hours, 90 ~ 99 points and 100 points the number of people, and output display results. (2008-05-07, Asm, 2KB, 下载19次)
9200用的是ht9200与isd1100,它们的语音输出都是通过一个电阻及电容后并在一起送到一个三极管进行放大的。...A20:Anitya,你的方法我试了一下,还是拨不通,自动拨号时可以听得到微弱的拨号音,但电话一点反映也没有,看来只有用
9200 with the ht9200 with isd1100. their voice output through a resistor and capacitor to together and after a triode amplification. ... A20 : Anitya, your approach I tried it, or the allocation of the passageway, Automatic dialing can hear faint dial tone, but the phone did not reflect the point, it seems Only (2006-09-08, Asm, 1KB, 下载165次)
一个数字时钟的程序
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※资料提供：上海齐济电子有限公司※
※联系电话：21-65630199 ※
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16F877秒表源程序，带注解
该源程序已在实验板上调试通过，读者可直接引用，并可以利用软件编程的灵活性，加以拓展，实现更为复杂的功能。
a digital clock procedures****************************************************** information : Shanghai Qi Ji Electronics Co., Ltd.** Contact telephone : 21-65630199****************************************************** 16F877 stopwatch source , annotated source in the experimental board debugging, readers may directly quoted, and can use software programming flexibility, be broadened to more complex functions. (2006-01-06, Asm, 12KB, 下载15次)
步骤一 查壳步骤二 脱壳步骤三 试运行程序 发现突破点步骤四 W32DASM 寻找突破点(可以跳过)步骤五 查询软件的编译类型步骤六 采用GetVBRes v0.51 对付VB程序步骤七 用W32Dasm载入修改后的文件步骤八 制作内存补丁 KeyMake v1.73
steps to check a shell two steps Shelling three steps trial operation procedures found breakthrough steps to find a breakthrough W32DASM four points (can skip) Step 5 inquiries software compiler used six types of steps to deal with VB GetVBRes v0.51 procedural steps included seven NodeManager Professional with the revised document produced eight steps memory patch KeyMake v1 .73 (2005-05-10, Asm, 2174KB, 下载99次)