采用DMA模式 通道0-3，A0 A1 A2 A3 (2022-07-07, C/C++, 1103KB, 下载0次)
http://www.pudn.com/Download/item/id/1657165260699853.html给定n个矩阵{A1,A2....An}，其中Ai与Ai+1是可以相乘的，判断这n个矩阵通过加括号的方式相乘，使得相乘的次数最少! 以矩阵链ABCD为例，按照矩阵链长度递增计算最优值 矩阵链长度为1时，分别计算出矩阵链A、B、C、D的最优值 矩阵链长度为2时，分别计算出矩阵链AB、BC、CD的最优值 矩阵链长度为3时，分别计算出矩阵链ABC、BCD的最优值 矩阵链长度为4时，计算出矩阵链ABC (2022-04-22, C/C++, 113KB, 下载0次)
http://www.pudn.com/Download/item/id/1650635640160836.html
基于51单片机数码管静态显示以及秒表的proteus仿真
Line I Addr Code Source
1: N 0000 ORG 0000H
2: ;CLR F0
3: 0000 20 90 FD MAIN: JB P1.0,$
4: ;CPL F0
5: ;SCN:JNB F0,MAIN
6: 0003 78 00 L1: MOV R0,#0
7: 0005 11 0F LP1: ACALL DIS
8: 0007 11 25 ACALL DELAY1S
9: 0009 08 INC R0
10: 000A B8 64 F8 CJNE R0,#100,LP1
11: 000D 01 03 AJMP L1
12: 000F E8 DIS: MOV A,R0
13: 0010 75 F0 0A MOV B,#10
14: 0013 84 DIV AB
15: 0014 90 01 00 MOV DPTR,#TABLE
16: 0017 93 MOVC A,@A+DPTR
17: 0018 F5 80 MOV P0,A
18: 001A E5 F0 MOV A,B
19: 001C 93 MOVC A,@A+DPTR
20: 001D F5 A0 MOV P2,A
21: 001F 22 RET
22: 0020 20 91 FD L2:JB P1.1,$
23: 0023 80 DB SJMP MAIN
24: (2021-04-23, C/C++, 102KB, 下载0次)
可以实现流水灯的花样控制可以通过proteus查看并更改
Line I Addr Code Source
1: N 0030 ORG 30H
2: N 00C8 CYC1 EQU 200
3: N 007D CYC2 EQU 125
4: 0030 74 FE MOV A,#0FEH ;
5: 0032 F5 A0 MOV P2,A
6: 0034 7A 07 MOV R2,#7
7: 0036 23 DOWN: RL A ;
8: 0037 11 4A ACALL DEL50
9: 0039 F5 A0 MOV P2,A
10: 003B DA F9 DJNZ R2,DOWN
11: 003D 7A 07 MOV R2,#7
12: 003F 03 UP: RR A ; (2021-04-23, C/C++, 45KB, 下载0次)
BF-Scalper, it is a Scalper EA, please try it on your way.
BF-Scalper, it is a Scalper EA, please try it on your way. (2021-04-09, C/C++, 31KB, 下载1次)
62304提供一个医疗软件开发的框架，并指出框架下每个过程的要求，62304将过程分解为若干活动，活动分解为若干任务
62304 provides a framework for medical software development and identifies the requirements for each process within the framework. 62304 decomposes the process into several activities, which are decomposed into several tasks (2021-02-03, C/C++, 1812KB, 下载2次)
摩托罗拉E6开发参考的一些资料,详细的讲了一些关键的技术，深入浅处XScale嵌入式系统(全本)。
MOTOROLA E6 A1200 Dev (2021-01-03, C/C++, 27975KB, 下载0次)
摩托罗拉E6开发参考的一些资料,详细的讲了一些关键的技术
MOTOROLA E6 A1200 Dev M.......ok (2021-01-03, C/C++, 81277KB, 下载2次)
摩托罗拉E6的电路图，里面包含了一些芯片资料。
MOTOROLA E6 A1200 E2 (2021-01-03, C/C++, 8735KB, 下载5次)
//参考 《常用算法程序集 （C语言描述 第三版)》
//最小二乘法
//x[n] y[n] 已知输入
//n输入点个数
//a[m] 返回m-1次拟合多项式的m个系数
//m 拟合多项式的项数,即拟合多项式的最高次为m-1
//dt[3] dt[0]返回拟合多项式与各数据点误差的平方和，
dt[1]返回拟合多项式与各数据点误差的绝对值之和
dt[2]返回拟合多项式与各数据点误差的绝对值的最大值
//拟合多项式的输出
//Y(x) = a0 + a1(x-X) + a2(x-X)^2 + …… am(x-X)^m
// 其中X为已知点x的平均值
Refer to common algorithm assembly (C language description, Third Edition)
Least square method
X [n] y [n] known input
N number of input points
A [M] returns m coefficients of M-1 degree fitting polynomial
The number of terms of m-fitting polynomial, that is, the highest degree of fitting polynomial is M-1
DT [3] DT [0] returns the sum of squares of the fitting polynomial and the errors of each data point,
DT [1] returns the sum of the absolute values of the fitting polynomial and the errors of each data point
DT [2] returns the maximum value of absolute error between fitting polynomial and each data point (2020-11-27, C/C++, 1KB, 下载0次)
配合中移onenet网络平台使用
1.修改esp8266.c下的wifi账号及密码
2.修改onenet.c下的PROID、SERIAL和PSWD
2.指令说明：
1.平台侧协议数据：
查询温度：01 03 0001 0001 D5CA
查询湿度：01 03 0002 0001 25CA
3.公式
1.温度：A0 / 100
2.湿度：A0 / 100
Use with China Mobile onenet network platform
1. Modify the wifi account and password under esp8266.c
2. Modify PROID, SERIAL and PSWD under onenet.c
2. Instructions:
1. Platform side protocol data:
Query temperature: 01 03 0001 0001 D5CA
Query humidity: 01 03 0002 0001 25CA
3. Formula
1. Temperature: A0/100
2. Humidity: A0/100 (2020-11-20, C/C++, 329KB, 下载2次)
This project is for porting the g723.1A to uclinux on the bf-533 target!
This project is for porting the g723.1A to uclinux on the bf-533 target! (2020-10-28, C/C++, 2232KB, 下载0次)
Shannon编码步骤：
1、将信源符号按概率从大到小的顺序排列，
p(a1)≥ p(a2)≥…≥ p(an)
2、确定满足下列不等式的整数Ki，
－log2 p(ai) ≤ Ki < 1－log2 p(ai)
3、令P(a1)=0，用Pi表示第i个码字的累加概率，
Pi=sum_{k=1}^{i-1} p(ak)
4、将Pi用二进制表示,并取小数点后Ki位作为符号ai的编码。
Shannon coding steps:
1. The source symbols are arranged in order of probability from large to small
2. Determine the integer ki satisfying the following inequality
3. Let P(A1)= 0, and PI denotes the cumulative probability of the i-th codeword,
4. PI is represented in binary system,and Ki bit after decimal point is taken as the code of symbol AI. (2020-09-06, C/C++, 1KB, 下载0次)
本软件包用于 DL/T 645 协议的采集与数据处理。在硬件层的移植（主要针对于串口收发数据）完成之后， 用户仅需调用一个API即可完成针对于特定协议（DL/T 1997 或 DL/T 2007）的标识符数据读取、处理与存储。使用户无需关注请求数据的封包与接收数据的解包等复杂的协议内部操作，真正做到 一键采集。
This software package is used for DL / T 645 protocol acquisition and data processing. After the porting of hardware layer (mainly for serial port receiving and sending data), users only need to call an API to complete the reading, processing and storage of identifier data for specific protocols (DL / T 1997 or DL / T 2007). Users do not need to pay attention to the complex internal operation of the protocol such as the packet of the request data and the unpacking of the received data, so as to realize the one key acquisition. (2020-09-01, C/C++, 29KB, 下载9次)
AVL树有不同的版本。通过初始化一个空的AVL树来启动您的程序。程序接受一行作为输入。输入行包含n个“修改移动”，用空格分隔(1≤n≤100)。可用的
修改举措
?Aint(字符A后跟一个1到100之间的int值):A3表示将值3插入AVL树中。如果3已经在树中，什么都不做。
?Dint(字符D后跟1到100之间的int值):D3表示将值3删除到AVL树中。如果3不在树中，什么都不做。
然后，在输入之后正好有一个完成步骤(PRE或POST或IN):如果完成步骤是PRE，那么应该按预先顺序打印出树(在当前情况下)。如果树为空，则打印为空。否则，打印用空格分隔的值。POST和IN的处理方式类似。
不需要担心无效的输入。样本输入1:A1 A2 A3 IN
示例输出1:1 2 3
样本输入2:A1 A2 A3 PRE
样本输出2:2 1 3样本输入3:A1 D1 POST样本输出3:空
There are different versions of AVL trees. Start your program by initializing an empty AVL tree. The program accepts one line as input. The input line contains n "modify moves" separated by Spaces. The available Modification measures (2020-08-25, C/C++, 1KB, 下载0次)
入门简单的算法，进行匹配，bf算法，简单的匹配
BF algorithm, simple matching (2020-07-02, C/C++, 2KB, 下载0次)
这是一个0.97奇迹登陆器 是仿三剑客写出来的 跟三剑客登陆器一样 功能一样 登陆器上注册 加点洗红 等等
It is a miracle lander is imitation 0.97 Three Musketeers The Three Musketeers landers to write out the same function with the same point on the lander registration plus wash red and so on (2020-06-30, C/C++, 4784KB, 下载1次)
设有一线性表A=（a0,a1,..., ai,...an-1)，其逆线性表定义为A'=( an-1,..., ai,...,a1, a0)，设计一个算法，将线性表逆置，要求线性表仍占用原线性表的空间。
There is a linear table a = (A0, A1,..., AI,... An-1), whose inverse linear table is defined as a '= (an-1,..., AI,..., A1, A0). An algorithm is designed to invert the linear table, which requires that the linear table still occupies the space of the original linear table. (2020-06-18, C/C++, 1KB, 下载0次)
Source Plugin - GameServer 0.93.02 (97N/97J)
Source Plugin - GameServer 0.93.02 (97N/97J) (2020-06-17, C/C++, 373KB, 下载0次)
stm8s系列接受烟雾传感器的数据，并将其发送到OLED显示器进行显示用
Stm8s series receives the data of smoke sensor and sends it to OLED display for display (2020-06-11, C/C++, 1659KB, 下载1次)