这是美国数学建模大赛97年的a题一种解决方法是利用计算机仿真的方法
This is a solution to the 1997 "A" problem of the American Mathematical Modeling contest, which is based on the method of computer simulation. (2018-11-24, Dev C++, 3KB, 下载0次)
给定n个矩阵构成的一个链<A1,A2,…,An>其中i 1,2,…,n,矩阵Ai的维数为pi-1pi,对乘积A1
A chain of given n Matrices (2018-11-22, Dev C++, 2KB, 下载0次)
题目描述
传说中有一种蜜汁序列特别甜，所以爱吃甜的强渣学长特别喜欢这种序列。。。
蜜汁序列的定义如下：对于一个长度为n的序列a1,...,an，如果这个序列的n个前缀和全部非负，即若a1> 0,a1+a2> 0,...,a1+a2+...+an> 0，则称a序列是蜜汁序列。。。
显然一些蜜汁序列可以分成更多的蜜汁序列，例如1 2这个蜜汁序列可以分成1和2两个蜜汁序列，现在有一个长度为n的蜜汁序列，要求你把他分成若干连续的段，使得每段都是一个蜜汁序列，问最多可以分成多少段？
输入
多组用例，每组用例首先输入一个整数n表示给出的蜜汁序列长度，之后输入n个整数a1,a2,...,an表示该序列的n个元素，以文件尾结束输入
输出
对于每组用例，输出一个整数占一行，表示该序列最多可以分成多少个蜜汁序列
数据范围
用例不超过10组，1< n< 10^6，-10^4< ai< 10^4（i 1,2,...,n）
样例输入
1
1
3
1 2 3
样例输出
1
3
Title Description
There is a legend of the honey series especially sweet, so sweet strong slag seniors love this series...
The definition of honey sequences are as follows: for a length sequence of A1, N, an,... If the sequence of the N prefix and all non negative, i.e. a1> 0, a1+a2> 0,..., a1+a2+...+an> 0, said a sequence is a sequence of honey...
Obviously some honey honey sequence can be divided into more sequences, such as the 12 series of honey can be divided into 1 and 2 two honey series, now has a length of honey sequence n, ask you to put him into several consecutive segments, each segment is a sequence of honey, ask most can be divided into many segments?
input
Many groups of cases, each case first enter an integer n indicating honey sequence length are given, then input n integers A1, A2,..., an said that the sequence of n elements, the tail end of the input file
output
For each case, output one integer per line, said the most sequence can be divided into how (2016-09-07, Dev C++, 1KB, 下载1次)