似乎您正在从引脚A0读取模拟电压，并将其转换为实际电压值。然后，每秒通过串行通信打印该值。
It seems like you re reading an analog voltage from pin A0 and converting it to a real voltage value. Then, you re printing this value over serial communication every second. (2024-04-01, C++, 0KB, 下载0次)
三星Galaxy Tab A7|t500的统一设备树（gta4lwifi）
Unified Device Tree for Samsung Galaxy Tab A7 | t500 (gta4lwifi) (2024-03-02, C++, 0KB, 下载0次)
C中的实时编译器演示++
Just-In-Time Compiler Demo in C++ (2024-02-19, C++, 0KB, 下载0次)
Bf解释器和编译器
Bf interpreter and compiler (2024-02-03, C++, 0KB, 下载0次)
引导ROM，用于将固件映像加载到Arty A7的CHERIoT Ibex版本
Boot ROM for loading firmware images onto the CHERIoT Ibex build for the Arty A7 (2023-12-24, C++, 0KB, 下载0次)
Bentley-Ottoman直线扫描算法的实现，以找到给定线段集的交点
Implementation of the Bentley Ottoman Line Sweep Algorithm to find the points of intersection of a given set of line segments (2022-04-25, C++, 0KB, 下载0次)
Obf-优化bf（编程语言、转发器和编译器，
Obf - Optimised bf (Programming language, transpiler and compiler, (2023-10-27, C++, 0KB, 下载0次)
北京邮电大学计算机科学与技术大三上编译原理课内作业,作业得分97(李文生),
In class assignment of Principles of Compilation in the third year of Computer Science and Technology at Beijing University of Posts and Telecommunications, with a score of 97 (Li Wensheng), (2021-01-09, C++, 0KB, 下载0次)
最终Burn Alpha 2012。Alpha最终燃烧港至Libretro（0.2.97.24）。，
Final Burn Alpha 2012. Port of Final Burn Alpha to Libretro (0.2.97.24)., (2022-03-27, C++, 0KB, 下载0次)
最终燃烧Alpha到Libretro的弃用端口（v0.2.97.43）。，
Deprecated port of Final Burn Alpha to Libretro (v0.2.97.43)., (2018-11-02, C++, 0KB, 下载0次)
使用二次误差度量进行曲面简化，SIGGRAPH 97（清华大学计算机图形学课程项目），
Surface simplification using quadric error metrics，SIGGRAPH 97 ( Course project for Computer Graphics, Tsinghua University), (2019-09-11, C++, 0KB, 下载0次)
问题描述 给定n个矩阵A1,A2,…,An,其中,Ai与Aj+1是可乘的,i 1,2,…,n-1, 你的任务是要确定矩阵连乘的运
The problem describes the given n matrices A _ (1) A _ (1) A _ (2),. Ani, where Ai and Aj 1 are multiplicative 1 / 2,. N-1, your task is to determine the operation of matrix multiplication (2018-09-06, C++, 7KB, 下载0次)
给定n个矩阵构成的一个链<A1,A2,…,An>其中i 1,2,…,n,矩阵Ai的维数为pi-1pi,对乘积A1 (2017-12-08, C++, 3KB, 下载1次)
http://www.pudn.com/Download/item/id/1512700238787576.html
Comparison on negotiaition algorithms using a tournament based approach
Comparison on negotiaition algorithms using a tournament based approach (2011-01-05, C++, 45KB, 下载1次)
2、 矩阵（二）
编写C++程序完成以下功能：
（1） 假定矩阵大小为4×5（整型）；
（2） 矩阵空间采用new动态申请，保存在指针中；
（3） 定义矩阵初始化函数，可以从cin中输入矩阵元素；
（4） 定义矩阵输出函数，将矩阵格式化输出到cout；
（5） 定义矩阵相加的函数，实现两个矩阵相加的功能,结果保存在另一个矩阵中；
（6） 定义矩阵相减的函数，实现两个矩阵相减的功能,结果保存在另一个矩阵中；
（7） 动态申请三个矩阵：A1、A2、A3；
（8） 初始化A1、A2；
（9） 计算并输出A3 = A1加A2，A3 = A1减A2；
（10） 释放矩阵空间。
2, matrix (2)
The preparation of C++ program to accomplish the following functions:
(1) assumes that matrix size of 4 × 5 (integer)
(2) matrix space with new dynamic applications, stored in the pointer
(3) defines the matrix initialization function, you can enter the matrix elements from the cin
(4) defines the matrix of output function, the matrix format the output to cout
(5) defines the matrix, the sum of the function, the sum of two matrices to achieve the functions of a matrix stored in another
(6) defines a function of matrix subtraction, subtract two matrices to achieve the function, the results stored in another matrix
(7) dynamic applications for three matrices: A1, A2, A3
(8) to initialize A1, A2
(9) to calculate and output of A3 = A1 plus A2, A3 = A1 by A2
(10) release matrix space. (2009-09-06, C++, 1KB, 下载20次)
Instead of finding the longest common
subsequence, let us try to determine the
length of the LCS.
Then tracking back to find the LCS.
Consider a1a2…am and b1b2…bn.
Case 1: am=bn. The LCS must contain am,
we have to find the LCS of a1a2…am-1 and
b1b2…bn-1.
Case 2: am≠bn. Wehave to find the LCS of
a1a2…am-1 and b1b2…bn, and a1a2…am and
b b b
b1b2…bn-1
Let A = a1 a2 … am and B = b1 b2 … bn
Let Li j denote the length of the longest i,g g
common subsequence of a1 a2 … ai and b1 b2
… bj.
Li,j = Li-1,j-1 + 1 if ai=bj
max{ L L } a≠b i-1,j, i,j-1 if ai≠j
L0,0 = L0,j = Li,0 = 0 for 1≤i≤m, 1≤j≤n.
Instead of finding the longest commonsubsequence, let us try to determine thelength of the LCS . (2009-01-20, C++, 1KB, 下载3次)