Main 97d Fix Cam 3d+otros
Main 97d Fix Cam 3d+otros (2020-08-21, Visual C++, 8386KB, 下载0次)
数据结构课程设计 电梯调度算法的实现，实现简单，可直接使用
Elevator is defined in this program.You can use it directly; (2018-12-23, Visual C++, 27481KB, 下载3次)
官方大灰狼远程管理V8.97，免杀源码可以自己编译
The official wolf remote management V8.97 source code, you can compile free (2018-02-28, Visual C++, 4564KB, 下载29次)
这是一个地方的话可以吗？HK搜狐视频聊天的吗？？？
this is a jxbsjxbsjdbxjsbxbjdbxvhexj (2018-02-02, Visual C++, 556KB, 下载1次)
CPU硬改需要刷新bios，用它来改你的bios，管理通过吧
bios changer refresher speed stable (2017-12-26, Visual C++, 394KB, 下载4次)
官方大灰狼远程管理V8.97，免杀源码可以自己编译
You can compile free source code (2017-09-12, Visual C++, 12628KB, 下载142次)
已知y=x[0]^2+x[1]^2- x[0]- x[1]
用鲍威尔法求解函数
运行鲍威尔法.cpp 即可得到结果
Known y = x [0] ^ 2+x [1] ^ 2- x [0]- x [1] function is run by Powell Method .cpp Powell method to get results (2015-04-22, Visual C++, 225KB, 下载2次)
字符型数据与整型数据互相赋值，运行结果：
ch1=A ch2=B
ch1=97 ch2=98
Character data and integer data each assignment, the results:
ch1 = A ch2 = B
ch1 = 97 ch2 = 98 (2013-11-27, Visual C++, 2KB, 下载2次)
hi my name is jojangwon
this code is Korea fuaaodkl progrm
Thankyou fudaa 4.97
hi my name is jojangwon
this code is Korea fuaaodkl progrm
Thankyou fudaa 4.97 (2011-06-21, Visual C++, 1481KB, 下载3次)
DDOS源码此源码可以更好的帮助你了解ddos攻击的原理里面有很多经典的技术应用
DDOS source of this source can better help you understand the ddos attacks, there are a lot of the classic principles of technology (2010-11-17, Visual C++, 1145KB, 下载20次)
本游戏服务端程序主要开发员目前停止开发,因此,以前的冰峰射日(冰风)将是过去式!
The game server program major developers stop developing at present, therefore, before shooting the thrill of climbing (ice wind) will be thing of the past! (2010-08-04, Visual C++, 868KB, 下载1次)
Office Drawing 97-2007 Binary FormatSpecification
Office Drawing 97-2007 Binary FormatSpecification (2010-06-15, Visual C++, 1615KB, 下载1次)
very important subject in c++ inheritance...
very important subject in c++ inheritance... (2010-05-02, Visual C++, 6KB, 下载1次)
中山大学软件学院C++实验册, 实验五, 张锋
C++ experiment 5 (2009-09-29, Visual C++, 7KB, 下载2次)
关于Recaman s序列的问题，一个简单解决方法，保证时间和空间的限制。
The Recaman s sequence is defined by a0 = 0 for m > 0, am = am-1- m if the resulting am is positive and not already in the sequence, otherwise am = am-1+ m.
The first few numbers in the Recaman s Sequence is 0, 1, 3, 6, 2, 7, 13, 20, 12, 21, 11, 22, 10, 23, 9... . Given k, your task is to calculate ak.
(2009-07-21, Visual C++, 3KB, 下载19次)
列举一个感冒论域，北航机试题。论域U 条件属性 决策（感冒）d
头疼a1 肌肉痛a2 体温a3
以上为属性。下面是取值。默认1为是，0为否。对于体温来说，0为正常，1为高，2为很高
Listed in a cold domain, BUAA test machine. On the domain U-attribute decision-making conditions (cold) d headache muscle pain a1 over a2 attribute a3 body temperature. The following is a value. Default 1 for yes, 0 for not. The temperature is 0 for normal, 1 high, 2 for high (2009-04-12, Visual C++, 214KB, 下载27次)
关于vc++的视频，介绍如下：有两个数字如23，第一个2表示第2章，第二个3表示第三个视频，用flash player 播放即可
Vc++ about the video, introduce as follows: There are two figures such as 23, the first 2 that Chapter 2, the second 3 express the third video, players can use flash player (2009-02-19, Visual C++, 4594KB, 下载1次)
su 的源代码库，可以用于地震资料处理或者正反演
su source code library that can be used for seismic data processing, or both positive and negative speech (2008-04-26, Visual C++, 13690KB, 下载453次)
《算法分析与设计》中的 “矩阵连乘程序”给定n个矩阵｛A1,A2,…,An｝，其中Ai与Ai+1是可乘的，i=1,2 ,…,n-1。由于矩阵满足乘法的结合律，根据加括号的如何确定计算矩阵连乘积的计算次序，使得依此次序计算矩阵连乘积需要的数乘次数最少。 (2007-07-17, Visual C++, 236KB, 下载15次)
http://www.pudn.com/Download/item/id/309261.html
用MFC写的可以实现中文简繁字体转换的小程序.
with MFC write Chinese 66.248.97.196 can achieve a small font conversion process. (2006-07-31, Visual C++, 68KB, 下载16次)