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按平台查找All Dev C++(17) 

[源码/资料]

图的遍历; 输入一个无向铁通讯网图,用Prim和Kruskal算法计算最小生成树并输出; 输入一个无向铁路交通图、始发站和终点站,用Dijkstra算法计算从始发站到终点站的最短路径。
Traversal of graphs; Find the minimum cost spanning tree of communication network. Input an undirected railway traffic map, starting station and terminal, and use Dijkstra algorithm to calculate the shortest path from the starting station to the terminal. (2018-12-09, Dev C++, 240KB, 下载1次)

http://www.pudn.com/Download/item/id/1544343133235804.html

[系统/网络安全] indusuryWep

网业文件转换成txt文件,方便阅读,不错,可以用
Web industry files converted to txt files, easy to read, good, can use (2018-12-02, Dev C++, 35KB, 下载0次)

http://www.pudn.com/Download/item/id/1543692314909955.html

[进程与线程] developeis_interffce

仿MSN(网易泡泡)界面,从事及时通信开发人员,不错的
Imitation MSN (NetEase bubble) interface, engaged in timely communication developers, good (2018-11-28, Dev C++, 484KB, 下载0次)

http://www.pudn.com/Download/item/id/1543416568385223.html

[其他] qbrzopi359

三角网的生成算法,是win32控制台程序,能自动构成Delauney三角网,
Triangulation generation algorithm, is the win32 console program, can automatically constitute Delauney triangulation, (2018-11-28, Dev C++, 43KB, 下载0次)

http://www.pudn.com/Download/item/id/1543406081532833.html

[生物医药技术] zkazb

高手写的所有acm例程 在acm zju edu cn 上的题目的例程
A routine for all acm routines written by a master on a topic on acm zju edu cn (2018-11-23, Dev C++, 285KB, 下载0次)

http://www.pudn.com/Download/item/id/1542981174822777.html

[系统/网络安全] IIDWUT

自己的ac代码 在acm zju edu cn 上的题目
The title of your own ac code on acm zju edu cn (2018-11-22, Dev C++, 23KB, 下载0次)

http://www.pudn.com/Download/item/id/1542822729674295.html

[人工智能/神经网络/深度学习] 479254

本程序是“拓补排序AOV网 ”,非常方便使用,希望大家能够喜欢,
This procedure is "extension sort AOV net", very convenient to use, I hope you can like, (2018-11-21, Dev C++, 41KB, 下载0次)

http://www.pudn.com/Download/item/id/1542732304596901.html

[进程与线程] GSM-idiit

GSM核心交换网典型故障处理傻瓜手册 rar
GSM core exchange network typical troubleshooting idiot manual ra (2018-09-22, Dev C++, 136KB, 下载0次)

http://www.pudn.com/Download/item/id/1537556472985582.html

[系统编程] 264644

900 1800MHz TDMA数字蜂窝移动通信网移动应用部分(Phase2+)技术规范报批稿
Technical Specification for Mobile Application part (Phase2+) of 900 1800MHz TDMA Digital Cellular Mobile Communication Network (2018-09-21, Dev C++, 235KB, 下载0次)

http://www.pudn.com/Download/item/id/1537545196947555.html

[其他] fangsong_GB2312_Downza.Cn

chinese font fangsong_gb2312
chinese font fangsong_gb2312 (2018-04-22, Dev C++, 2317KB, 下载1次)

http://www.pudn.com/Download/item/id/1524367731345938.html

[USB编程] hjlatile

利用NAT来映射端口实现CDMA无线数传模块数据中心的组网方式 (2018-04-16, Dev C++, 952KB, 下载1次)

http://www.pudn.com/Download/item/id/1523824414223649.html

[USB编程] kxjtti

华为3G核心网规划 内部资料 精品 第三代移动通信技术 (2018-01-13, Dev C++, 1779KB, 下载2次)

http://www.pudn.com/Download/item/id/1515803484966227.html

[其他] 无向图两点间简单路径

若无向图表示高速公路网,其中顶点表示城市,边表示城市之间的高速公路。试设计一个找路程序,获取两个城市之间的所有简单路径
If an undirected graph is used to express a highway network, the vertices represent the city, and the side represents the expressway between the cities. Try to design a path finding program to get all the simple paths between two cities (2018-01-12, Dev C++, 1KB, 下载3次)

http://www.pudn.com/Download/item/id/1515765391260895.html

[数据结构] Allpath

问题描述 若用无向图表示高速公路网,其中顶点表示城市,边表示城市之间的高速公路。试设计一个找路程序,获取两个城市之间的所有简单路径。 基本要求 (1) 输入参数:结点总数,结点的城市编号(4位长的数字,例如电话区号,长沙是0731),连接城市的高速公路(用高速公路连接的两个城市编号标记)。 (2) 输入 要求取所有简单路径的两个城市编号。 (3) 将所有路径(有城市编号组成)输出到用户指定的文件中。
Problem descriptionIf use undirected graph said freeways, with vertex said city, edge said highway between the two cities.Try to design a route program, obtain all simple paths between the two cities.  The basic requirements(1) input parameters: the total number of nodes, the nodes of the city number (4 digits long Numbers, telephone area code, for example, changsha is 0731), connected to the city expressway (with high-speed highway connects the two cities of number tags).(2) input requirements take number all simple paths of the two cities.(3) will all paths (a number of city) output to the user specified file. (2017-01-02, Dev C++, 3KB, 下载4次)

http://www.pudn.com/Download/item/id/1483329801874060.html

[OA办公系统] yjy

中国研究员专业网俱乐部活动会议纪要(2015-10-26) 会议时间: 2015年10月24日(周六)下午14:00 会议主题:好公司的讨论 会议纪要: 观点一: 我们对Go-Goal首页进行了修改,现在首页显示的是每日牛股池,我们按照每日涨幅高低进行排名。牛股头条的逻辑主要来源于重要新闻、业绩不错以及卖方报告强烈推荐。每天的研究报告大概有4、5百个,我们把它进行精选,每天大概20几个,我们称之为牛股头条。这里提供的是有业绩、有事件的公司,但是事件的失败率很高。另外一个模块叫寻宝游戏,整个10月份(从10月8日开始)到现在,其中红相电力、协鑫集成涨幅都不错。这个模块1、4、7、10月份是最有用处的(也是仅限这4个月份使用),10月是季报的第一个月,无法证伪,但大概率能挣钱。
Minutes of the club activities (2015-10-26) Meeting time: October 24, 2015 (Saturday) PM 14:00 Meeting topic: Discussion of good company Meeting minutes: One point: We are on the first page of this go goal was modified, now displayed on the homepage of is daily Niugu pool, we in accordance with the daily increase of high and low ranking. Logic Niugu mainly comes the important news headlines, good performance and the seller report strongly recommended. Daily report about four, five hundred, we put it to every day about 20 several, we call for the Niugu headlines. There is a performance, there are events of the company, but the failure rate of the event is very high. Another module called treasure hunt game. The month of October starting October 8 until now. The red power, GCL integrated or are good. This module 1, 4, 7, October is the most useful (and only limited the four month use), October is the first month of the Quarterly Bulletin, cannot be falsified, but a high probabi (2015-12-25, Dev C++, 348KB, 下载1次)

http://www.pudn.com/Download/item/id/1451029867853485.html

[Linux/Unix编程] DM9621A_for_customer

DM9621,一款USB转以太网的芯片,内含Linux下的驱动以及参考设计,拿来可以直接画板子用了。
DM9621, turn a USB Ethernet chip, embedded Linux under the driver as well as the reference design, it can directly draw the board. (2015-07-23, Dev C++, 3360KB, 下载26次)

http://www.pudn.com/Download/item/id/1437621264351340.html

[教育系统应用] 1022

浙大 编程能力测试 的甲级题目 第1022 数字图书馆问题 http://www.patest.cn/contests/pat-a-practise/1022
http://www.patest.cn/contests/pat-a-practise/1022 A Digital Library contains millions of books, stored according to their titles, authors, key words of their abstracts, publishers, and published years. Each book is assigned an unique 7-digit number as its ID. Given any query a reader, you are supposed to output the resulting books, sorted in increasing order of their ID s. (2015-06-03, Dev C++, 1KB, 下载4次)

http://www.pudn.com/Download/item/id/1433312125786818.html
总计:17