Repository pour客户端lourd de lépreuve E5 du BTS SIO-SLAM
Repository pour client lourd de l épreuve E5 du BTS SIO - SLAM (2024-04-02, Others, 0KB, 下载0次)
BTS 2ème Anne e SIO SLAM pour lépreuve E5项目
Projet de BTS 2ème année SIO SLAM pour l épreuve E5 (2024-03-08, Others, 0KB, 下载0次)
代码部分参考了大佬的可视化调度器[https: github.com AkatsukiCC huawei2019-with- visualization,没有加调度器,用融合了地杰斯特拉的贪婪思想的A- star算法计算出来最短路径,然后将车辆按照路径长短和车辆速度两个维度进行...](https: github.com AkatsukiCC huawei2019-with- visualization%EF%BC%8C%E6%B2%A1%E6%9C%89%E5%8A%A0%E8%B0%83%E5%BA%A6%E5%99%A8%EF%BC%8C%E7%94%A8%E8%9E%8D%E5%90%88%E4%BA%86%E5%9C%B0%E6%9D%B0%E6%96%AF%E7%89%B9%E6%8B%89%E7%9A%84%E8%B4%AA%E5%A9%AA%E6%80%9D%E6%83%B3%E7%9A%84A-star%E7%AE%97%E6%B3%95%E8%AE%A1%E7%AE%97%E5%87%BA%E6%9D%A5%E6%9C%80%E7%9F%AD%E8%B7%AF%E5
The code part refers to the visual scheduler of Big Brother [https: github.com AkatsukiCC huawei2019 with - visualization, without adding a scheduler, the shortest path is calculated using the A-star algorithm that integrates Dijestra s greedy idea, and then the vehicle is carried out according to the two dimensions of path length and vehicle speed...] (https: github.com AkatsukiCC huawei2019 with - visualization% EF% BC% 8C% E6% B2% A1% E6% 9C% 89% E5% 8A% A0% E8% B0% 83% E5% BA% A6% E5% 99% A8% EF% BC% 8C% E7% 94% A8% E8% 9E% 8D% E5% 90% 88% E4% BA% 86% E5% 9C% B0% E6% 9D% B0% E6% 96% AF% E7% 89% B9% E6% 8B% 89% E7% 9A% 84% E8% B4% AA% E5% A9% AA% E6% 80% 9D% E6% 83% B3% E7% 9A% 84A star% E7% AE% 97% E6% B3% 95% E8% AE% A1% E7% AE% 97% E5% 87% BA% E6% 9D% A5% E6% 9C% 80% E7% 9F% AD% E8% B7% AF% E5 (2019-12-07, Python, 0KB, 下载0次)
随机密钥生成-ADC-Arty-A7，，
Random-Key-Generation-ADC-Arty-A7,, (2023-08-06, Python, 0KB, 下载0次)
计量经济学2019-A1，，
econometrics2019-A1,, (2020-03-23, R, 0KB, 下载0次)
ORB_SLAM2系统Rviz可视化方案(实现详细介绍见 励志献身SLAM 的 阿翔 博客:[http: ttshun.com 2018 10 14 ORB- SLAM2%E7%B3%BB%E7%BB%9FRviz%E5%8F%AF%E8%A7%86%E5%8C%96%E6%...](http: ttshun.com 2018 10 14 ORB- SLAM2%E7%B3%BB%E7%BB%9FRviz%E5%8F%AF%E8%A7%86%E5%8C%96%E6%96%B9%E6%A1%88 ),
ORB_ SLAM2 system Rviz visualization scheme (see A Xiang s blog dedicated to SLAM for the implementation details: [http: ttshun.com 2018 10 14 ORB - SLAM2% E7% B3% BB% E7% BB% 9FRviz% E5% 8F% AF% E8% A7% 86% E5% 8C% 96% E6%...] (http: ttshun.com 2018 10 14 ORB - SLAM2% E7% B3% BB% E7% BB% 9FRviz% E5% 8F% AF% E8% A7% 86% E5% 8C% 96% E6% 96% B9% E6% A1% 88), (2019-11-29, C++, 0KB, 下载0次)
自然排序顺序字符串比较：“a1”<“a12”，
natural sort order string comparison: "a1" < "a12", (2022-06-25, C, 0KB, 下载0次)
BF共享哈希，，
BF-Shared-Hashing,, (2021-07-23, C++, 0KB, 下载0次)
用标准E6电阻器构建任何电阻器
Build any resistor from standard E6 resistors (2018-07-27, Mathematica, 0KB, 下载0次)
用matlab展现遗传算法的计算过程。例子为求0.711*t1-0.084*(a0*t4*t1/(t2-t1+t3))+0.7*(t4-t3)+0.091*t2+0.162*(a0*t2*t4/(t2-t1+t3))这个看起来很复杂的式子的最小值,各个变量的约束条件在代码里写了出来。
Matlab is used to show the calculation process of genetic algorithm. The example is to find the minimum value of the seemingly complex formula 0.711*t1-0.084*(a0*t4*t1/(t2-t1+t3)+0.7* (t4-t3)+0.091*t2+0.162* (a0*t2*t4/(t2-t1+t3)). The constraints of each variable are written in the code. (2019-07-07, matlab, 1KB, 下载8次)
频散特性曲线，各向同性材料，模式为1-3，A0 S0
lamb waves Dispersion characteristic curve, isotropic material, mode 1-3, A0 S0 (2018-06-10, matlab, 1KB, 下载6次)
验证哥德巴赫才:任何一个充分大的偶数N(≥4),可以用两个素数之和表示.
如 4=2+2 6=3+3 8=3+5 98=17+79
Verify Goldbach before: Any one sufficiently large even number N (≥ 4), can be expressed the sum of two primes. Such as 4 = 2+2 6 = 3+3 8 = 3+5 98 = 17+79 (2009-11-09, Pascal, 1KB, 下载24次)
求满足 M > N > 0 的两个正整数之和的最大公约数.
Order to meet the M> N> 0, two positive integers and the greatest common divisor. (2009-11-09, Pascal, 1KB, 下载30次)
用VB编写的多项式拟合程序
Public Function funPolynomial(Num As Long, x() As Single, y() As Single, Degree As Integer, AA() As Single) As Long
多项式曲线拟合 y=a0+a1*x+a2*x^2+an*x^n
Num为输入数据点个数
x()为输入数据点横坐标组成的数组
y()为输入数据点纵坐标组成的数组
Degree为要拟合的多项式曲线次数
AA() 为待求系数，为输出项
failed to translate (2009-10-16, Visual Basic, 5KB, 下载117次)
矩阵运算：求逆、转置、相乘等，然后通过矩阵运算求多项式纠正的值，多项式如：X=a0+a1*x+a2*y+a3*x*x+a4*x*y+a5*y*y
Y=b0+b1*x+b2*y+b3*x*x+b4*x*y+b5*y*y
Matrix operations: inversion, transpose, multiply, etc., and then through the matrix for computing the value of correct polynomial, polynomials, such as: X = a0+ a1* x+ a2* y+ a3* x* x+ a4* x* y+ a5* y* y Y = b0+ b1* x+ b2* y+ b3* x* x+ b4* x* y+ b5* y* y (2009-06-10, Visual C++, 2KB, 下载12次)
随机生成100个100以内的数，并查找输入的数是否在数组中。
100 100 randomly generated within a few, and find whether the number entered in the array. (2009-04-26, Java, 2KB, 下载1次)
一维多项式多组求值，利用系数预处理法对多项式p(x)=an-1x^n-1+an-2x^n-2+...+a1x+a0,进行多组求值。其中n=2^k
Many one-dimensional polynomial evaluation group, using coefficient polynomial preconditioning method p (x) = an-1x ^ n-1+ an-2x ^ n-2+...+ a1x+ a0, for many Group evaluated. One of n = 2 ^ k (2009-04-03, C/C++, 1KB, 下载4次)
使用FFT实现的两个多项式相乘的算法。
输入文件：
第一行为(n-1)
第二行为第一个多项式系数序列 第三行为第二个多项式系数序列
系数序列的格式为：an,an-1,an-2 ,…, a1,a0
输出文件：result5.txt
格式为结果多项式的系数序列。
序列格式为：an,an-1,an-2 ,…, a1,a0（此n与输入中的n不同）
Implementation of both the use of FFT polynomial multiplication algorithms. Input file: the first act (n-1) the second act of the first polynomial coefficient sequence of the third act of the second polynomial coefficient sequence coefficient sequence format: an, an-1, an-2, ..., a1, a0 output file: result5.txt format for the results of polynomial coefficient sequence. Sequence format: an, an-1, an-2, ..., a1, a0 (the n with the input of the n different) (2009-03-15, Visual C++, 2KB, 下载34次)
对于给定的n 个整数a0, a1,., an-1 组成的序列，计算相应的亲兄弟元素位置序列。
For a given n integers a0, a1,., An-1, composed of sequences, calculation of the corresponding elements of the location of sequence brothers. (2007-11-13, Visual C++, 1KB, 下载4次)
用最小二乘法拟合曲线y=a0+a1*x+a2*x^2+a3*x^3+...+an*x^n 的vc源码
using the method of least squares fitting curve y = a0 a1 a2* x* x* a3 ^ 2 x ^ 3 ... an* x ^ n vc FO (2007-06-01, Visual C++, 2KB, 下载96次)